conc/3
conc([1,2], [3,4], L)
conc(Beg, End, [1,2,3,4])
conc(Beg, [End], [1,2,3,4])
conc(Beg, [Mid|End], [1,2,3,4])
Result is A + B
=:=
, =\=
, >
, <
, >=
, =<
>=
in =<
ne izgledata kot puščicimod
, rem
shiftleft/2
shiftright/2
rev/2
palindrome/1
evenlen/1
+ oddlen/1
len/2
sum/2
min/2
max/2
sublist/2